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In the below reaction,the reactive intermediate formed is

 

$\begin{array}{1 1}(a)\;:CCl_2&(b)\;CHCl_2^{\ominus}\\(c)\;:CCl_2^{\ominus}&(d)\;CCl_3\end{array}$

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1 Answer

Hence (a) is the correct answer.
answered Feb 27, 2014 by sreemathi.v
 
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