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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Waves
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The magnetic field in a plane electromagnetic wave is given by $B_y= 2 \times 10^{-7} \: \sin (0.5\times10^3x+1.5\times10^{11}t)T$ The wavelength and frequency of the wave are

$\begin {array} {1 1} (a)\;0.26\: m \: and \: 239 \: MHz & \quad (b)\;1.26\: cm \: and \: 23.9 \: GHz \\ (c)\;1.26\: m \: and \: 23.9 \: MHz & \quad (d)\;0.26\: cm \: and \: 2.39 \: GHz \end {array}$

 

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1 Answer

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Comparing the given equation with $B_y = B_o \: \sin \bigg[2 \pi \bigg( \large\frac{x}{\lambda} + \large\frac{t}{T} \bigg) \bigg]$
We get, $ \lambda = \large\frac{2 \pi}{ 0.5 \times 10^3\: m }$$= 1.26 \: cm$
and $ \large\frac{1}{T}$ $ = Frequency =\large\frac{1.5 \times 10^{11} }{2 \pi}$$ = 23.9 \: GHz$
Ans : (b)

 

answered Feb 27, 2014 by thanvigandhi_1
edited Oct 3, 2014 by thagee.vedartham
 

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