logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Waves
0 votes

Find the energy of a photon in electron volt of microwaves having wavelength $3mm.(1\: eV = 1.6 \times 10^{-19}J)$

$ (a) 41.4 \times 10^{-2}\; eV\quad (b) 4.14 \times 10^{-4}\; eV$
$(c) 4.14 \times 10^{-2}\; eV\quad (b) 41.4 \times 10^{-4}\; eV$
Can you answer this question?
 
 

1 Answer

0 votes
Energy = $\large\frac{hc}{\lambda} $ $=\large\frac{ 6.6 \times 10^{-34} \times 3 \times 10^{8}}{3 \times 10^{-3}}$$= \large\frac{6.6 \times 10^{-23} J}{ 1.6 \times 10^{-19}\: eV}$$ = 4.14 \times 10^{-4}\: eV$
Ans : (b)
answered Feb 27, 2014 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...