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# The equation of normal to the curve y=tan x at (0,0) is___________.

• Slope of a line is $ax+by+c=0$ is $- \bigg( \large\frac{ Coefficient\: of \: x}{ Coefficient\: of \: y} \bigg)$
• If $y = f(x),\: then \: \bigg( \large\frac{dy}{dx} \bigg)_p =$ slope of the normal to $y = f(x)$ at point $p$
$y = \tan \: x$
differentiating w.r.t $x$ we get,
$\large\frac{dy}{dx}=\sec^2x$
The slope of the tangent at $(0,0)$ is
$\large\frac{dy}{dx_{(0,0)}}= \sec^2 (0)$
But $\sec 0=1$