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The angle at which first order reflection will occur when X-ray of wavelength $1.54A^{\large\circ}$ are diffracted by the atoms of a crystal ; the interplanar distance is $4.04A^{\large\circ}$

$(a)\;22^\circ20'\qquad(b)\;10^\circ59'\qquad(c)\;33^\circ32'\qquad(d)\;15^\circ24'$

1 Answer

$\lambda = 2d\sin\theta$
$1.54 = 2\times4.04\sin\theta$
$\theta = \sin^{-1}(0.191)$
$= 10.98^{\large\circ}$
$=10^{\large\circ}59'$
Hence answer is (b)
answered Feb 27, 2014 by sharmaaparna1
 

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