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Silver (atomic weight = $107.88$) crystallises with f.c.c lattice for which the side length of the unit cell is $4.0774\overset{\circ}{A}$. Density of $Ag$ is $10.53\; g\;cm^{-3}$. Calculate the Avogadro's number.


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Avogadro No. = $\large\frac{n\times at.wt}{density\times a^3}$
Hence answer is (b)
answered Feb 27, 2014 by sharmaaparna1

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