Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Silver (atomic weight = $107.88$) crystallises with f.c.c lattice for which the side length of the unit cell is $4.0774\overset{\circ}{A}$. Density of $Ag$ is $10.53\; g\;cm^{-3}$. Calculate the Avogadro's number.


Can you answer this question?

1 Answer

0 votes
Avogadro No. = $\large\frac{n\times at.wt}{density\times a^3}$
Hence answer is (b)
answered Feb 27, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App