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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Waves
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The displacement $y$ of a wave travelling in the $x$ - direction is $y = 10^{-4} \sin(600t – 2x + \large\frac{\pi}{3})m$, where, $x$ is in $m$ and $t$ is in $s$. The speed of the wave motion in $m/s$ is

$\begin {array} {1 1} (a)\;300 & \quad (b)\;600 \\ (c)\;1200 & \quad (d)\;200 \end {array}$


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Comparing the given equation with a standard equation of wave, $y = a\: \sin (\omega t – kx + \phi) $
we get, $ \omega = 600\: and\: k = 2$
So, velocity $= \large\frac{\omega}{k} $$= \large\frac{600}{2}$$ = 300 m/s$
Ans : (a)
answered Feb 27, 2014 by thanvigandhi_1

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