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Find the shortest distance between the lines : $\large \frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}$$ \: and \: \large\frac{x-2}{3}=\frac{y-4}{4}=\frac{z-5}{5} $ Also, find equation of the shortest distance.
cbse
class12
modelpaper
2012
sec-c
q29
math
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asked
Jan 13, 2013
by
thanvigandhi_1
edited
Jul 22, 2013
by
sreemathi.v
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Find the foot of the perpendicular from ( 0, 2, 3 ) on the line \(\large \frac{x+3}{5} = \frac{y-1}{2} = \frac{z+4}{3}\). Also find the length of perpendicular.
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Dec 24, 2012
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