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Enthalpy =


(a) $T^2 [\frac{\delta(G/T)}{\delta T}]_P$
(b) $-T^2 [\frac{\delta(G/T)}{\delta T}]_P$
(c) $T^2 [\frac{\delta(G/T)}{\delta T}]_V$
(d) $-T^2 [\frac{\delta(G/T)}{\delta T}]_V$

1 Answer

Answer: $-T^2 [\frac{\delta(G/T)}{\delta T}]_P$
It can be derived from the definition of Entropy and Gibbs free energy, that, $[\frac{\delta(G/T)}{\delta T}]_P = - \frac{\Delta H}{T_2}$
$\Longrightarrow \Delta H =-T^2 [\frac{\delta(G/T)}{\delta T}]_P$
This is one of the forms of Gibbs-Hemholtz equation.
answered Feb 27, 2014 by mosymeow_1
 

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