(a) $10^{-8}$

(b) $10^{-22.22}$

(c) $10^{-33.55}$

(d) none of these

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Answer: $10^{-33.55}$

$\Delta G^\circ$ = 46.06 kcal/mol = $46.06 \times 1000 \times 4.184 J/mol$

$\Delta G^\circ = -$RT ln $K_P = -2.303$ RT log $K_P$

$\Longrightarrow 46.04 \times 1000\times 4.184 = -2.303 \times 8.31 \times 300$ log $K_P$

$\Longrightarrow$ log $K_P = -33.55$

$\Longrightarrow K_P = 10^{-33.55}$

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