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The amount of heat evloved when 500 $cm^3$ 0.1 M HCl is mixed with 200 $cm^3$ of 0.2 M NaOH is


(a) 2.292 kJ
(b) 1.292 kJ
(c) 0.292 kJ
(d) 3.292 kJ

1 Answer

Answer: 2.292 kJ
500 $cm^3$ of 0.1 M HCl = $\frac{500 \times 0.1}{1000}$ = 0.05 mol
200 $cm^3$ of 0.2 M NaOH = $\frac{200 \times 0.2}{1000}$ = 0.04 mol
$\therefore$ 0.04 moles of NaOH is neutralised by 0.04 mol of HCl.
$\therefore$ Heat released = $57.3 \times 0.04 = 2.292$ kJ
answered Feb 27, 2014 by mosymeow_1
 

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