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A $1.0\; g$ sample of substance A at $100^\circ C$ is added to $100\; mL$ of $H_2O$ at $25^\circ C$. Using separate $100\; mL$ portions of $H_2O$, the procedure is repeated with substance $B$ and then with substance $C$. How will the final temperatures of the water compare?

image
(a) $T_C > T_B > T_A$
(b) $T_B>T_A>T_C$
(c) $T_A>T_B>T_C$
(d) $T_A=T_B=T_C$

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Answer: $T_A>T_B>T_C$
Heat evolved or absorbed, $Q=ms\Delta t$
Where,
m= mass of the substance,
s = specific heat,
$\Delta t$ = temperature difference
Therefore, more specific heat more is the heat content and more the rise in temperature. Thus, the correct order of final temperature is $T_A>T_B>T_C$.
answered Feb 27, 2014 by mosymeow_1
 

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