Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Atoms
0 votes

The half life of radioactive radon is 3.8 days . The time , at end of which $\;\large\frac{1}{20}^{th}\;$ of radon sample will remain undecayed is

$(a)\;18 \;days\qquad(b)\;16.5 \;days\qquad(c)\;17.6 \;days\qquad(d)\;19.2 \;days$

Can you answer this question?

1 Answer

0 votes
Answer : (b) $\;16.5 \;days$
Explanation :
Equation for decay of radioactive nuclei will be
$N=N_{0} e^{-\lambda t}$
Where $\;\lambda\large\frac{ln 2}{t_{\large\frac{1}{2}}}=\large\frac{ln 2}{38}$
$\large\frac{N_{0}}{20}$$=N_{0} e^{-\large\frac{ln2}{.8}\;t}$
answered Feb 27, 2014 by yamini.v
edited Mar 25, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App