Browse Questions

The binding energy of two nuclei A & B are X & Y . Two atoms of A fuse to give one atom of B an energy P is released . Then

$(a)\;P=Y-2X\qquad(b)\;P=Y-X\qquad(c)\;P=2Y-X\qquad(d)\;P=Y+X$

Answer : (a) $\;P=Y-2X$
Explanation :
During fusion , binding energy of daughter nucleus is always greater then total binding energy of parent nuclei . The difference of binding energies is released . Hence $\;P=Y-2X$