Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Atoms
0 votes

Two radioactive materials A & B have decay constants 12X & X respectively . If initially they have same no.of nuclei , then ratio of no. of nuclei of A to B will be $\;\large\frac{1}{e}\;$ after a time

$(a)\;1/12 X\qquad(b)\;1/11X\qquad(c)\;1/32X\qquad(d)\;1/224X$

Can you answer this question?

1 Answer

0 votes
Answer : (b) $\;\large\frac{1}{11X}$
Explanation :
$\large\frac{N_{A}}{N_{B}}=\large\frac{1}{e}\;$ or
$\large\frac{N_{0} e^{-12Xt}}{N_{0} e^{-Xt}}=\large\frac{1}{e}$
Initially both have same no . of nuclei say no .
or $\;e=\large\frac{e^{-Xt}}{e^{-12Xt}}$$=e^{11Xt}$
answered Feb 28, 2014 by yamini.v
edited Mar 25, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App