logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Nitrogen
0 votes

The correct order of base strength of the three isomers of methoxy aniline is

$\begin{array}{1 1}(a)\;P-CH_3OC_6H_4NH_2 > M-CH_3OC_6H_4NH_2 > O-CH_3OC_6H_4NH_2\\(b)\;P-CH_3OC_6H_4NH_2 > O-CH_3OC_6H_4NH_2 > M-CH_3OC_6H_4NH_2\\ (c)\;O-CH_3OC_6H_4NH_2 > P-CH_3OC_6H_4NH_2 > M-CH_3OC_6H_4NH_2\\(d)\;\text{None of these}\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
$-OCH_3$ group II $e^{\ominus}$-releasing group by resonance from ortho and para positions and thus increses the availability of $e^{\ominus}$ on N atom making them more basic .Ortho Bomer weaker than para isomer because of the ortho effect in which the solvation of cation is sterically hindered.
Hence (b) is the correct answer.
answered Feb 28, 2014 by sreemathi.v
 
Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...