$(a)\;1:1\qquad(b)\;1:2\qquad(c)\;1:3\qquad(d)\;2:1$

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Every constituent has two tetrahedral voids.

In CCP lattice atoms = $\large\frac{1}{8}\times8+6\times\large\frac{1}{2}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=1+3$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=4$

$\therefore Tetrahedral\; Void = 4\times2$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=8$

Thus ratio = 4:8 :: 1:2

Hence answer is (b)

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