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The major product obtained on heating of $CH_3CH_2CH_2CH_2N^{\oplus}(CH_3)_3OH^{\ominus}$

$\begin{array}{1 1}(a)\;CH_3CH_2CH=CH_2&(b)\;CH_3-CH=CH_2\\(c)\;CH_3CH_2CH_2-CH_3&(d)\;CH_3CH=CH-CH_2\end{array}$

1 Answer

  • Hofmann elimination, also known as exhaustive methylation, is a process where an amine is reacted to create a tertiary amine and an alkene by treatment with excess methyl iodide followed by treatment with silver oxide, water, and heat.
Above reaction is Holfmann elimination.The removal of H atom from the $\beta$ carbon.
Hence (a) is the correct answer.
answered Feb 28, 2014 by sreemathi.v
edited Mar 29, 2014 by mosymeow_1