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States of Matter: Solid State
In a face centred cubic arrangement of A and B atoms whose A atoms are at the corner of the unit cell and B atoms at the face centered. One of the A atom is missing from one corner in unit cell. The simplest formula of compound is
$(a)\;A_7B_3\qquad(b)\;AB_3\qquad(c)\;A_7B_{24}\qquad(d)\;A_4B_3$
jeemain
chemistry
class12
ch1
states-of-matter
solid-state
packing-in-crystalline-solids
easy
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asked
Feb 28, 2014
by
sharmaaparna1
retagged
Jul 15, 2014
by
balaji.thirumalai
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1 Answer
No. of atoms of A from corners of unit cell = $\large\frac{7}{8}$
No. of atoms of B from faces of unit cell = 3
Thus A:B = $\large\frac{7}{8} :3$
$\;\;\;\;\;\;\;\;Or = 7:24$
Thus the formula is $A_7B_{24}$
Hence answer is (c)
answered
Feb 28, 2014
by
sharmaaparna1
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