$(a)\;XY_2\qquad(b)\;XY\qquad(c)\;XY_3\qquad(d)\;X_3Y$

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No. of X-atoms per unit cell = $\large\frac{8}{8}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=1$

No. of Y-atoms per unit cell = $\large\frac{6}{2}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=3$

Thus the formula is $XY_3$

Hence answer is (c)

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