# The cannizzaro reaction of benzaldehyde and formaldehyde in the presence of $NaOH$ gives, $(i)\;C_6H_5CH_2OH\; ;(ii)\; C_6H_5COONa\; ; (iii)\; HCOONa \; ; (iv) \;CH_3OH$

$(a)\;(i)\; and\;(iii) \\ (b) \; (ii)\;and \;(iii) \\ (c) \;(i)\;and \;(iv) \\ (d)\;(ii)\;and (iv)$

Because of bulky nature of ohenyl group $OH$ will attack to given case
Hence a is the correct answer.