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The AM radio wave bends appreciably round the corners of a $1m \times 1m$ board but the FM wave only negligibly bands. If the average wavelength of the AM and FM waves are $ \lambda_a$ and $\lambda_f$ , then

$\begin {array} {1 1} (a)\;\lambda_a > \lambda_f & \quad (b)\;\lambda_a = \lambda_f \\ (c)\;\lambda_a < \lambda_f & \quad (d)\;\text{ can't be determined} \end {array}$


1 Answer

Bending of wave around the corner occurs, if the dimension of the board is comparable to the wavelength of the wave.
From the given information we know that $ \lambda_a$ since no bending of FM waves take place two possibilities may arise whether $ \lambda_f>>1m \: or\: \lambda_f<<1m$.
$ \lambda_f>>1m \: or\: \lambda_f<<1m$.
So, information is insufficient to determine whether $ \lambda_a>\lambda_f$ is comparable to $1m$. But, or $\lambda_a<\lambda_f.$
Ans : (d)
answered Feb 28, 2014 by thanvigandhi_1

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