Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Waves
0 votes

An object is placed at some distance from a radio station. If the interval between transmission and reception of pulses is $2.66 \times 10^{-2}\: sec$, then the distance is:

$\begin {array} {1 1} (a)\;4000\: km & \quad (b)\;2000\: km \\ (c)\;3000\: km & \quad (d)\;2500\: km \end {array}$


Can you answer this question?

1 Answer

0 votes
Time difference between transmission and reception of pulses $= T = 2.66 \times 10^{-2}s$
So, time requires for pulse to travel from station to the object $ = t =\large\frac{T}{2}$$ = \large\frac{2.66 \times 10^{-2}}{ 2}$
$= 1.33 \times 10^{-2}s$
So, distance $= t \times$ speed of radio wave in air,
since radio waves are electromagnetic waves its speed is the speed of light
$= 1.33 \times10^{-2}s \times3 \times10^8m/s = 3990 \: km \sim 4000 \: km$
Ans : (a)


answered Feb 28, 2014 by thanvigandhi_1
edited Oct 3, 2014 by thagee.vedartham

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App