logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Communication Systems
0 votes

A TV tower has a height of $100\: m$. The area covered by the TV broadcast, if radius of the earth is $6400\: km$, will be:

$\begin {array} {1 1} (a)\;380 \times 10^7 m^2 & \quad (b)\;402 \times 10^7 m^2 \\ (c)\;595 \times 10^7 m^2 & \quad (d)\;440 \times 10^7 m^2 \end {array}$

 

Can you answer this question?
 
 

1 Answer

0 votes
Distance covered by the broadcast, $d = \sqrt{2hR}$ , where R is the radius of Earth
$= \sqrt{(2 \times 100 \times 6400 \times 10^3 )}$
$= 35777.087\: m$
So, area covered $= \pi d^2$
$= 3.14 \times 35777.087^2 m^2$
$= 401.9 \times 10^7 m^2 \sim 40^2 \times 10^7 m^2$
Ans : (b)

 

answered Feb 28, 2014 by thanvigandhi_1
edited Oct 3, 2014 by thagee.vedartham
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...