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An enantiometrically pure acid is treated with racemix mixture of an alcohol having carbon. The ester formed will be :

(a) Optically active mixture (b)Pure enantiomer (c)Meso compound (d) Racemic mixture
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The optically active acid will react with (+) and (-) forms of alcohol present in racemic mixture to form two stereoisomeric esters each one of which contains two different chiral c-atoms and hence are optically active (ie) an optically active mixture is produced.
Hence a is the correct answer.
answered Feb 28, 2014 by meena.p

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