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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Waves
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We can establish an instantaneous displacement current of $1\: A$ in the space between the two plates of a $1\: \mu\: F$ parallel plate capacitor by varying voltage at the rate of

$\begin {array} {1 1} (a)\;10^9 V/s & \quad (b)\;10^{12}V/s \\ (c)\;10^8 V/s & \quad (d)\;10^6V/s \end {array}$


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$I_D = \in_o d \large\frac{ \phi_E}{dt} = \in_o  \large\frac{d(EA)}{dt}$
$= \in_o A \:\large\frac{ d}{dt}$
$= \in_o A\: \large\frac{d(V/d)}{ dt}$
$= \in_oA/d \times \large\frac{dV}{dt}$$ = \large\frac{CdV}{dt}$
$\Rightarrow \large\frac{dV}{dt}$$ = \large\frac{I_D}{C}$
Ans : (d)


answered Feb 28, 2014 by thanvigandhi_1
edited Mar 3, 2014 by thanvigandhi_1

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