$(a)\;2 litre,4litre\qquad(b)\;1.5 litre,4.5litre\qquad(c)\;1.59litre,4.62litre\qquad(d)\;3.82litre,4.62litre$

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Since 100mL blood has 0.02g $O_2$ and 0.08g $CO_2$

$\therefore$ 10,000mL blood has 2g $O_2$ and 8g $CO_2$

Now PV = $\large\frac{w}{m}RT$

For $O_2 : 1\times V = \large\frac{2}{32}\times0.0821\times310$

$V_{O_2}$ = 1.59 litre

For $CO_2 : 1\times V = \large\frac{8}{44}\times0.0821\times 310$

$V_{CO_2}$ = 4.62 litre

Hence answer is (c)

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