$(a)\;The\; same\qquad(b)\;110\;atm\qquad(c)\;90\;atm\qquad(d)\;80\;atm$

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- The ideal gas equation is : $\quad\large pV=nRT$

The reaction shown is:

$N_2+3H_2 = 2NH_3$

With a deduction of 4 moles of the $N_2/H_2$ mixture, 2 moles of Ammonia is obtained.

So, from 20% of the $N_2/H_2$ mixture, 10% Ammonia is produced, reducing the total mixture by 10%.

Given, the system is a closed vessel, Volume, V = constant and temperature, T = 100 atm.

$\therefore \quad \large p \propto n$

Since, the total mixture left is 90%, there will be a 10% decrease in the pressure on the mixture i.e. 90 atm.

Hence answer is (c)

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