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An LPG cylinder contain 15kg of butane gas at $27^{\large\circ}C$ and 10 bar pressure. The cylinder linked and it was found that after 4 days , the mass of the gas left in cylinder was only 10 kg. How much drop in pressure was occured in each day?

$(a)\;0.52 bar\qquad(b)\;0.833bar\qquad(c)\;1.6 bar\qquad(d)\;1.832bar$

1 Answer

Since Loss of mass in 4 days = 5 kg
$\therefore$ Loss of mass in 1 day = $\large\frac{5}{4}$kg
$\therefore$ Pressure due to 15kg = 10 bar
Pressure due to $\large\frac{5}{4}kg = \large\frac{10\times5}{15\times4}$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=0.833 bar$
Hence answer is (b)
answered Mar 1, 2014 by sharmaaparna1

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