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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Electromagnetic Induction

Area under $V_L - t$ graph gives

 

The potential difference across a 2H inductor as function of time is shown in figure. At time $t=0$, current is zero.

$\begin {array} {1 1} (a)\;\text{Current} & \quad (b)\;\text{Product of current} \\ (c)\;\text{Product of inductance and current} & \quad (d)\;\text{Product of inductance and change in current} \end {array}$

 

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1 Answer

Since $ V_L =L \large\frac{di}{dt}$
$\Rightarrow L\: di = V_L\: dt$
 Integrating on both sides
$ \Rightarrow L(i_f – i_i ) = \: _o\int^t \: V_L\: dt = $ area under $V_L-t $ graph
Ans : (d)

 

answered Mar 1, 2014 by thanvigandhi_1
edited Oct 8, 2014 by thagee.vedartham
 

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