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At room temperature , the rms speed of molecules of a certain diatomic gas is formed to be 1930 m/Sec . The gas is

$(a)\;H_2\qquad(b)\;F_2\qquad(c)\;O_2\qquad(d)\;Cl_2$

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$U_{rms} = \sqrt{\large\frac{3RT}{M}}$
$\;\;\;\;\;=\large\frac{3\times8.314\times30}{M} = 1930$
$M = 2\times 10^{-3}kg$
Hence answer is (a)
answered Mar 2, 2014 by sharmaaparna1
 

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