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The enolic form of acetone contains

(a) Nine $\sigma$ -bonds, One $\pi$ bond and two lone pairs.

(b) Eight $\sigma$ -bonds, two $\pi$ bonds and two lone pairs.

(c) Nine $\sigma$ -bonds, One $\pi$ bond and one lone pair.

(d) Nine $\sigma$ -bonds, two $\pi$ bond and one lone pair.

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1 Answer

So, Nine $\sigma$ -bonds, One $\pi$ bond and two lone pairs.
Hence a is the correct answer.
answered Mar 3, 2014 by meena.p
 

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