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A compound with empirical formula $CH_2O$ has a vapour density of 30. Its molecular formula is

$ (a)\;C_2 H_2O_2 \\ (b)\;C_2H_4O_2 \\ (c)\;C_3H_6O_3 \\ (d)\;C_6H_{12}O_6 $
Can you answer this question?

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Molecular weight $= 2 \times $vapour density
$\qquad=2 \times 30=60$
$\therefore$ Molecular formula = $ \large\frac{Molecuar \;weight }{Empirical \; formula \;weight }$$ \times E.F$
$\qquad= \large\frac{60}{30}$$ \times CH_2O$
$\qquad = C_2H_4O_2$
Hence b is the correct answer.
answered Mar 3, 2014 by meena.p

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