Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Nitrogen
0 votes

The correct order of basicity of below is


$ \begin{array}{1 1}(a)\;(I) > (II) > (III)&(b)\;(III) > (I) > (II)\\(c)\;(III) > (II) > (I)&(d)\;(II) > (I) > (III)\end{array}$

Can you answer this question?

1 Answer

0 votes
In this compound the lone pair is in an $SP^3$ hybrid orbital and there is no resonance (no $\pi$ system).So more basic.
$SP^2$ hybrid orbital-So more basic than the 1-lone pair in resonance.
However the order is $(III) > (I) > (II)$
Hence (b) is the correct answer.
answered Mar 3, 2014 by sreemathi.v
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App