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# The major product obtained on heating of below is

$\begin{array}{1 1}(a)\;CH_2-CH_3&(b)\;CH-CH_3\\(c)\;H_2C=CH_2&(d)\;CH_2CHCH_2CH_3\end{array}$

This compound has three $\beta$-hydrogen as labelled
(I) $\beta-1\rightarrow$more acidic $1^o\beta$
(II) $\beta-2\rightarrow$ less acidic $2^o\beta$
(III) $\beta-3\rightarrow$ less acidic $3^o\beta$
So the product is $CH_2=CH_2$