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A tertiary amine can be separated from a mixture of primary and tertiary amine using

$ \begin{array}{1 1}(a)\;C_6H_5SO_2Cl&(b)\;H_2SO_4\\(c)\;KOH&(d)\;\text{above all}\end{array}$

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$C_6H_5SO_2Cl$ is Hinsberg reagent.In this method primary amines react with HInsberg reagent (benzene sulphonyl chloride) while tertiary does not
$R-NH_2+C_6H_5SO_2Cl\rightarrow C_6H_5SO_2NHR$(N-alkyl benzene sulphonamide)+HCl
Hence (a) is the correct answer.
answered Mar 3, 2014 by sreemathi.v

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