Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Nitrogen
0 votes

A tertiary amine can be separated from a mixture of primary and tertiary amine using

$ \begin{array}{1 1}(a)\;C_6H_5SO_2Cl&(b)\;H_2SO_4\\(c)\;KOH&(d)\;\text{above all}\end{array}$

Can you answer this question?

1 Answer

0 votes
$C_6H_5SO_2Cl$ is Hinsberg reagent.In this method primary amines react with HInsberg reagent (benzene sulphonyl chloride) while tertiary does not
$R-NH_2+C_6H_5SO_2Cl\rightarrow C_6H_5SO_2NHR$(N-alkyl benzene sulphonamide)+HCl
Hence (a) is the correct answer.
answered Mar 3, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App