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What is the pressure of 2 mole of ammonia at $27^{\large\circ}C$ when its volume is 5 litre according to Van der Waal's equation? (a = 4.17 b = 0.03711)


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$(P+\large\frac{n^2a}{V^2})(V-nb) = nRT$
$P = \large\frac{nRT}{(V-nb)}-\large\frac{an^2}{V^2}$
$=9.33 atm$
Hence answer is (b)
answered Mar 3, 2014 by sharmaaparna1

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