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What is the pressure of 2 mole of ammonia at $27^{\large\circ}C$ when its volume is 5 litre according to Van der Waal's equation? (a = 4.17 b = 0.03711)

$(a)\;10.33atm\qquad(b)\;9.33atm\qquad(c)\;9.74atm\qquad(d)\;9.29atm$

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$(P+\large\frac{n^2a}{V^2})(V-nb) = nRT$
$P = \large\frac{nRT}{(V-nb)}-\large\frac{an^2}{V^2}$
$=\large\frac{2\times0.082\times300}{(5-2\times0.03711)}-\large\frac{4.17\times4}{25}$
$=9.33 atm$
Hence answer is (b)
answered Mar 3, 2014 by sharmaaparna1
 

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