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How many optical isomers are possible for the compound abdc - cabd?

(a) Two (b) Four (c) Three (d) One
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1 Answer

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The compound contains 2 chiral carbon atoms and it has a plane of symmetry.
Hence the number of optical isomers = $2^{n-1}+2^{n/2-1}$
$\qquad=2^{2-1}+2^{2/2-1}$
No. of . optical isomers =3
Hence c is the correct answer.
answered Mar 3, 2014 by meena.p
 

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