$\begin {array} {1 1} (a)\;\text{ Straight line} & \quad (b)\;\text{ Parabola} \\ (c)\;\text{Hyperbola} & \quad (d)\;\text{Exponential} \end {array}$

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For $t \leq 1s$

$V_L = 8t$

$ \Rightarrow L\: di = V_L dt$

$\Rightarrow \int\: Ldi = \int\: 8 \: tdt$

$\Rightarrow Li = \large\frac{8t^2}{2}$$ = 4t^2$

$ \Rightarrow i = 2t^2$

So, current versus time graph is a parabola.

For $1s \leq t \leq 2s,$

$V_L = 16 – 8t$

$ \Rightarrow \int \: L\: di = \int\: (16 – 8t)\: dt$

$ \Rightarrow Li = \large\frac{16t – 8t^2}{2}$

$ \Rightarrow i = 8t -2t^2$

So, $i$ vs $ t$ graph is a parabola

Ans : (b)

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