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In Kjeldahl's method, nitrogen present is estimated as

$ (a)\;N_2 \\(b)\;NO \\(c)\;NH_3\\(d)\;NO_2 $
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$N+ con C.H_2SO_4 \underrightarrow {\Delta} (NH_4)_2SO_4$
from orgain compound
$(NH_4)_2SO_4+ 2NaOH \to Na_2 SO_4+2H_2O+2NH_3$
$2NH_3 +H_2SO_4 \to (NH_4)_2SO_4$
So $NH_3$ is correct
Hence c is the correct answer.
answered Mar 4, 2014 by meena.p
 

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