$\begin {array} {1 1} (a)\;i & \quad (b)\;\large\frac{i}{4} \\ (c)\;\large\frac{i}{3} & \quad (d)\;\large\frac{i}{2} \end {array}$

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Displacement current, $I = \in_o\: \large\frac{d \phi E}{dt}$$ = \in_o A \large\frac{dE}{dt}$

$= \in_o A\: \large\frac{ d\bigg( \Large\frac{q}{\in_oA’} \bigg) }{ dt}$ where, $A’$ is area of each plate of capacitor

So, $I = \large\frac{A}{A’}$$ \times \large\frac{ dq}{dt}$$ = \large\frac{(a)(2a)dq}{(2a)(4a)dt}$

$ \large\frac{i}{4}$

Ans : (b)

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