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How many stereo isomers does this molecule have $CH_3CH =CHCH_2CHBrCH_3$

$ (a)\;8 \\(b)\;2\\(c)\;4\\(d)\;6 $
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The given compound may be written as
Both geometrical isomers (c is transform) and optical isomers is possible in the given compound.
No of optical isomers $=2^n=2^1=2$
Where n=no of optical isomers $=2+2=4$
So 4 is the answer
Hence c is the correct answer.
answered Mar 4, 2014 by meena.p

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