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An alkane with the formula $C_6H_{14}$ can be prepared by the hydrogenation of only two prepared by the hydrogenation of only two alkenes $(C_6 H_{12})$. IUPAC name of the alkane is :

$ (a)\;2,2 -Dimethyl butane \\(b)\;2,3 -Dimethyl butane\\(c)\;2- Methylpentane \\(d)\; n- Hexane $
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So it is $2,3 -Dimethyl butane$
Hence b is the correct answer.
answered Mar 4, 2014 by meena.p
 

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