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The IUPAC name of

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$ (a)\;5-OxO-4-hydroxy-2-pentanone \\(b)\;4-Hydroxy-5-al-2-Pentanone \\(c)\;2-Hydroxy-4-Oxopentanal \\(d)\;1-Al-4-OxO-2-Pentanol $
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Aldehyde > Ketone > Alcohol
$\therefore $ Aldhyde behaves as a functional group and numbering starts from terminal functional group.
$2-Hydroxy-4-Oxopentanal$ is correct
Hence c is the correct answer.
answered Mar 4, 2014 by meena.p
 
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