Browse Questions

# The IUPAC name of

$(a)\;5-OxO-4-hydroxy-2-pentanone \\(b)\;4-Hydroxy-5-al-2-Pentanone \\(c)\;2-Hydroxy-4-Oxopentanal \\(d)\;1-Al-4-OxO-2-Pentanol$

Aldehyde > Ketone > Alcohol
$\therefore$ Aldhyde behaves as a functional group and numbering starts from terminal functional group.
$2-Hydroxy-4-Oxopentanal$ is correct
Hence c is the correct answer.