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# If $'a'$ is the bond moment and $\theta$ is the bond angle between two bonds then the dipolemoment $\mu$ is given by

$\begin{array}{1 1}(a)\;\mu=a\cos \theta&(b)\;\mu=a\cos \large\frac{\theta}{2}\\(c)\;\mu=2a\cos \large\frac{\theta}{2}&(d)\;\mu=m^2\cos \large\frac{\theta}{2}\end{array}$

Dipolemoment $(\mu)=2a\cos \large\frac{\theta}{2}$
Where $a$=bond moment
$\theta$=bond angle between two bonds
Hence (c) is the correct answer.