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Increasing order of basic nature of $NH_3(I), CH_3NH_2(II) $ and -NH_2(III)( $ is

$ (a)\;III < II < I \\(b)\;I < II < III \\(c)\;III = II < I \\(d)\;III < I < II $
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Electrons withdrawing substituents decreases basicity whereas electron donating substituents increases basicity
$III < I < II $
Hence d is the correct answer.
answered Mar 5, 2014 by meena.p

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