Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Two separate bulbs contain gas A and gas B. The density of gas A is twice as that of B. The molecular mass of A is $\large\frac{1}{2}$ as that of B. If temperature is constant, the ratio of the pressure of A and B is :


Can you answer this question?

1 Answer

0 votes
  • Density of the gas $= \large\frac{Pressure\; \times Molecular \; mass}{RT}$
$d = \large\frac{PM}{RT}$
$\large\frac{d_A}{d_B} = 2$
$=\large\frac{P_A\times M_A}{P_B\times M_B}$
$=\large\frac{P_A}{P_B}\times \large\frac{1}{2}$
$\therefore \large\frac{P_A}{P_B} = 4$
Hence the ratio is 4:1
Thus answer is (c)
answered Mar 5, 2014 by sharmaaparna1
edited Mar 18, 2014 by mosymeow_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App