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The hybridisation of $XeOF_4$ molecule is

$\begin{array}{1 1}(a)\;sp^3d^2&(b)\; sp^3d\\(c)\;dsp^3&(d)\;sp^3\end{array}$

1 Answer

Square pyramidal shape of $XeOF_4$ with $sp^3d^2$ hybridisation.
Hence (a) is the correct answer.
answered Mar 5, 2014 by sreemathi.v
 

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