$(a)\;270mL\qquad(b)\;90mL\qquad(c)\;405mL\qquad(d)\;135mL$

$P\times30 = n_1\times R\times T$

If half of the mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth the original gas,

$\large\frac{P}{9}\times V = \large\frac{n_1}{2}\times R\times 3T$

$V = \large\frac{9\times 30\times 3}{2}$

$\;\;\;\;\;=405mL$

Hence answer is (c)

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