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A quantity of hydrogen gas occupies a volume of 30.0mL at a certain temperature and pressure. What volume of half of this mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth the original gas?

$(a)\;270mL\qquad(b)\;90mL\qquad(c)\;405mL\qquad(d)\;135mL$

1 Answer

$P\times30 = n_1\times R\times T$
If half of the mass of hydrogen occupy at triple the absolute temperature if the pressure were one-ninth the original gas,
$\large\frac{P}{9}\times V = \large\frac{n_1}{2}\times R\times 3T$
$V = \large\frac{9\times 30\times 3}{2}$
$\;\;\;\;\;=405mL$
Hence answer is (c)
answered Mar 5, 2014 by sharmaaparna1
edited Mar 18, 2014 by mosymeow_1
 

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