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If $V_0$ is the volume of the given mass of a gas at 273K and pressure P , then according to Charles's law the volume of same mass of gas at $10^{\large\circ}C$ and pressure P will be


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$PV_0 = nR\times273$
$PV = nR\times 283$
$\therefore V = \large\frac{283}{273} \times V_0$
Hence answer is (d)
answered Mar 5, 2014 by sharmaaparna1

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